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-4+4b=b^2
We move all terms to the left:
-4+4b-(b^2)=0
determiningTheFunctionDomain -b^2+4b-4=0
We add all the numbers together, and all the variables
-1b^2+4b-4=0
a = -1; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{-4}{-2}=+2$
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